How to compare two linear lists in Pascal?

Member

by kendall , in category: Other , 2 years ago

How to compare two linear lists in Pascal?

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2 answers

by cyril.littel , 2 years ago

@kendall 

Here's an example code for comparing two linear lists in Pascal:

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program CompareLinearLists;

type
  TList = array[1..10] of integer; // assume lists have maximum of 10 elements

var
  list1, list2: TList;
  isEqual: boolean;
  i: integer;
begin
  // initialize the lists with some values for testing purposes
  list1 := (1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
  list2 := (1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
  
  // compare the lists element by element
  isEqual := true;
  for i := 1 to 10 do // assume both lists have the same length
  begin
    if list1[i] <> list2[i] then
    begin
      isEqual := false;
      break;
    end;
  end;
  
  // print the result
  if isEqual then
    writeln('The lists are equal.')
  else
    writeln('The lists are not equal.');
end.


In this example code, we define a custom type TList that represents an array of integers with a maximum capacity of 10. We then initialize two instances of TList, named list1 and list2, and populate them with some values.


To compare the two lists, we use a boolean variable isEqual to keep track of whether the lists are equal or not. We then loop through the lists element by element using a for loop, comparing each element of list1 with the corresponding element of list2. If there is a mismatch between any element of the two lists, we set isEqual to false and break out of the loop.


Finally, we print the result based on the value of isEqual.


Note that in this example code, we assume that both lists have the same length. If you need to compare lists of different lengths, you should include additional logic to handle this case.

Member

by casper , a year ago

@kendall 

Also, note that in the example code above, the assignment of values to the lists (list1 and list2) is done using parentheses. However, in Pascal, arrays are typically assigned using square brackets.


Here's the modified code with square brackets:

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program CompareLinearLists;

type
  TList = array[1..10] of integer; // assume lists have maximum of 10 elements

var
  list1, list2: TList;
  isEqual: boolean;
  i: integer;
begin
  // initialize the lists with some values for testing purposes
  list1 := [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
  list2 := [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

  // compare the lists element by element
  isEqual := true;
  for i := 1 to 10 do // assume both lists have the same length
  begin
    if list1[i] <> list2[i] then
    begin
      isEqual := false;
      break;
    end;
  end;

  // print the result
  if isEqual then
    writeln('The lists are equal.')
  else
    writeln('The lists are not equal.');
end.


Note that both versions of the code are correct and will produce the same result. You can use either one based on your preference.

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